SOLUTION: Solve the equation. Round to 2 decimal places if needed. log(x)+log(3x-1)=1 I guess this one is confusing me because there isn't a base after the log. I know that I have to

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve the equation. Round to 2 decimal places if needed. log(x)+log(3x-1)=1 I guess this one is confusing me because there isn't a base after the log. I know that I have to      Log On


   

Question 859551: Solve the equation. Round to 2 decimal places if needed.
log(x)+log(3x-1)=1
I guess this one is confusing me because there isn't a base after the log. I know that I have to multiply (x)and(3x-1) because it is an addition problem, but not sure if I do that first or what to do.
Thanks in advance for the help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

no base 'after log' generally indicates base 10

log(x)+log(3x-1)=1

log(x)(3x-1)=1

 x(3x-1) = 10

 3x^2 - x - 10 = 0

 (3x + 5)(x - 2) = 0, 

          x = 2    (negative solution is an extraneous root)