SOLUTION: what are the measures of the sides of a right triangle with a hypotenuse of 3.2

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Question 859539: what are the measures of the sides of a right triangle with a hypotenuse of 3.2
Found 3 solutions by Fombitz, ewatrrr, Awesom3guy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You cannot tell what the measure of both sides are just given the hypotenuse.
A%5E2%2BB%5E2=3.2%5E2
You can choose one and calculate the other.
If I choose A, then
B=sqrt%283.2%5E2-A%5E2%29
For example,
A=1
B=sqrt%2810.24-1%29=3.04
and if
A=2
B=sqrt%2810.24-4%29=2.50
So you have to choose one and solve for the other, you can't solve for both.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

IF the sides are of equal in length 'x'

 x^2 + x^2 = (3.2)^2    |Pythagorean Theorem

  2x^2 = (3.2)^2

  2x^2 = 10.24

   x^2 = 5.12

    x = 2.26   (rounded to the nearest one-hundredth)

Answer by Awesom3guy(31) About Me  (Show Source):
You can put this solution on YOUR website!

No idea.
You need the length of one of the unknown sides.

Or, if the legs are equal (isosceles triangle) then we can do it like this (a is the length of the triangle's leg):
a%5E2+%2B+a%5E2+=+3.2%5E2
2a%5E2+=+10.24
a%5E2+=+5.12
a+=+sqrt5.12 or 2.26 to 2 decimal places.