Question 859438: Write an equation of the line that passes through (10,-4) and is perpendicular to the line whose equation is y = 2/5x - 8
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! y = 2/ 5 x + -8
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 2/5
The slope of a line perpendicular to the above line will be the negative reciprocal -2 1/2
Because m1*m2 =-1
The slope of the required line will be -2 1/2
m= -2 1/2 ,point ( 10 , -4 )
Find b by plugging the values of m & the point in
y=mx+b
-4 = -25 + b
b= 21
m= -5/2
The required equation is y = -5/ 2 x + 21
m.ananth@hotmail.ca
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