SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs
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Question 8594: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
Can someone help me? Thank you so much for any help! Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Let L = the length of one of the equal legs and B = the length of the base.
Write the equation for the perimeter of the triangle:
P = 2L + B = 29 cm. But L = 4B-8
P = 2(4B-8) + B = 29 Simplify and solve for B
8B - 16 + B = 29
9B - 16 = 29 Add 16 to both sides.
9B = 45 Divide both sides by 9.
B = 5 cm
L = 4B - 8
L = 4(5) - 8
L = 20 - 8
L = 12 cm.
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