SOLUTION: How do I break this down: Two consecutive negative integers are multiplied together. To this product is added the sum of the integer. If the result equals 41, determine the intege

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Question 859388: How do I break this down:
Two consecutive negative integers are multiplied together. To this product is added the sum of the integer. If the result equals 41, determine the integers.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
x = smallest integer

x(x+1) + (x + (x+1)) = 41
x^2 + x + 2x + 1 = 41
x^2 + 3x - 40 = 0
(x + 8)(x - 5) = 0
x = -8, x = 5

x is negative, so the integers are -8 and -7.