SOLUTION: How many milliliters of 8% hydrochloric acid and 15% hydrochloric acid to get 100 milliliters of solution that is 12.2% hydrochloric acid?

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Question 859008: How many milliliters of 8% hydrochloric acid and 15% hydrochloric acid to get 100 milliliters of solution that is 12.2% hydrochloric acid?
Found 2 solutions by josgarithmetic, mananth:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You need the densities.
Percent Weight_______density g/ml
8____________________1.0376
12.2_________________est. 1.059
15___________________1.0723

(referenced http://www.handymath.com/cgi-bin/hcltble3.cgi?submit=Entry ).

The equations rely on being strictly in percents weight per weight.
Let u = VOLUME of 8% acid
Let v = volume of 15% acid

%28u%2A8%2A1.0376%2Bv%2A15%2A1.0723%29%2F%28100%2A1.059%29=12.2, accounts for the percent concentration;
and
u%2Bv=100 should account well for the volumes.

Those two equations as a system will really be found to be two linear equations in variables u and v.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Percent ---------------- quantity
Hcl I 15.00% ---------------- x ml
Hcl II 8.00% ------ 100 - x ml
Mixture 12.20% ---------------- 100
Total 100 ml
15.00% x + 8.00% ( 100 - x ) = 12.20% * 100
15 x + 8 ( 100 - x ) = 1220
15 x + 800 - 8 x = 1220
15 x - 8 x = 1220 - -800
7 x = 420
/ 7
x = 60 ml 15.00% Hcl I
40 ml 8.00% Hcl II

m.ananth@hotmail.ca