SOLUTION: A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what

Algebra ->  Linear-equations -> SOLUTION: A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what       Log On


   

Question 85883: A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
44*T+48(T-1)=274
44T+48T-48=274
92T=274+48
92T=322
T=322/92
T=3.5 HOURS THEY WILL BE 274 MILES APART.
PROOF
44*3.5+48*2.5=274
154+120=274
274=274