SOLUTION: x^2-5x-14 <0

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Question 858782: x^2-5x-14 <0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-5x-14+%3C0
%28x%2B2%29%28x-7%29+%3C0
When x%3C-2, left hand side is negative*negative=positive, so not less than zero
When x%3E7, left hand side is positive*positive=positive, so not less than zero
When -2%3Cx%3C7, left hand side is positive*negative, so less than zero.
So x%5E2-5x-14%3C0 when -2%3Cx%3C7
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Verified by the graph
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graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-5x-14%29