SOLUTION: 1. The perimeter of a rectangle is 38 inches. If the length of the rectangle is six inches less than four times the width, find the area of the rectangle.
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-> SOLUTION: 1. The perimeter of a rectangle is 38 inches. If the length of the rectangle is six inches less than four times the width, find the area of the rectangle.
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Question 858573: 1. The perimeter of a rectangle is 38 inches. If the length of the rectangle is six inches less than four times the width, find the area of the rectangle. Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! Perimeter = 2L + 2W
2L + 2W = 38
L = 4W - 6 [the length of the rectangle is six inches less than four times the width]
Substitute the known value of L from the second equation into the first.
2(4W-6) + 2W = 38
Distribute
8W-12+2W = 38
Add the Ws
10W - 12 = 38
Add 12 to each side
10W = 50
Divide each side by 10
W = 5
.
If W is 5, then L =(4*5)-6
L = 20-6
L = 14
.
To find the area, multiply the length times the width.
5 * 14 = 70 square inches
