SOLUTION: One number is is 3 less than a second number. Twice the second number is 34 more than 4 times the first. Find the two numbers.
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-> SOLUTION: One number is is 3 less than a second number. Twice the second number is 34 more than 4 times the first. Find the two numbers.
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Question 858557: One number is is 3 less than a second number. Twice the second number is 34 more than 4 times the first. Find the two numbers. Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! Let A be the first number, and B the second.
A = B-3 [One number is is 3 less than a second number]
2B = 4A + 34 [Twice the second number is 34 more than 4 times the first.]
Substitute the known value of A from the first equation into the second.
2B = 4(B-3) + 34
Distribute
2B = 4B-12+34
Add
2B = 4B + 22
Subtract 22 from each side
2B - 22 = 4B
Subtract 2B from each side
-22 = 2B
Divide each side by 2
-11 = B
.
If B = -11, then A is -14.
Let's make sure this works.
twice -11 should be 34 more than 4x -14
-22 = 34 - 56
Success!
