SOLUTION: Y=2(x-1)^2+3 Find x-intercepts. Can you please show me how to find the x-intercepts. I know the vertex is 1,3.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Y=2(x-1)^2+3 Find x-intercepts. Can you please show me how to find the x-intercepts. I know the vertex is 1,3.      Log On


   

Question 85834: Y=2(x-1)^2+3
Find x-intercepts.
Can you please show me how to find the x-intercepts. I know the vertex is 1,3.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Y=2(x-1)^2+3
Find x-intercepts.
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Let y= 0 and solve for x:
2(x-1)^2+3 = 0
(x-1)^2 = -3/2
Since the square equals a negative value
x-1 is a complex number (not a Real Number).
So the x-intercepts are complex.
The graph of your function does not cross the x-axis.
There are no x-intercepts.
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C2%28x-1%29%5E2%2B3%29
Cheers,
Stan H.