Question 85823: log(3)(4x-7)=2
log(4)x+log(4)(x-3)=1
3^x+1=27
4^x-1=64
help me please!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Thought to remember: log is another name for exponent.
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log(3)(4x-7)=2
Here you are told "the log is 2"
So, 4x-7 = 3^2
4x-7=9
4x=16
x=4
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log(4)x+log(4)(x-3)=1
log(4)[x(x-3)]=1
Here you are told "the log is 1"
x(x-3)=4^1
solve for x
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3^(x+1)=27
Rewrite as
3^(x+1) = 3^3
x+1=3
x=2
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4^(x-1)=64
Rewrite as
4^(x-1) = 4^3
x-1=3
x=4
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Cheers,
Stan H.
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