SOLUTION: The question is Sean has 6 more dimes than nickels. If he has $3.15, how many of eaach coin does he have?
I tried the following:
0.05N + 0.10D = $3.15 and 6d=n however i get a
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-> SOLUTION: The question is Sean has 6 more dimes than nickels. If he has $3.15, how many of eaach coin does he have?
I tried the following:
0.05N + 0.10D = $3.15 and 6d=n however i get a
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Question 858211: The question is Sean has 6 more dimes than nickels. If he has $3.15, how many of eaach coin does he have?
I tried the following:
0.05N + 0.10D = $3.15 and 6d=n however i get a weird answer
You can put this solution on YOUR website! d count of dimes
n count of nickels
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d=n+6 and 0.05n+0.1d=3.15 which is n+2d=63.
The system most simplified is:
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d-n=6
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2d+n=63
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Just add the two equations to use Elimination Method.
This immediately gives 3d=66, meaning .
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