SOLUTION: 2^4*2^5= b*c^2*b^6*c^2=

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Question 85819: 2^4*2^5=
b*c^2*b^6*c^2=
Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
Hope your question is as follows...



+2%5E4+%2A+2%5E5+

Here you can use the law of exponents, that is +x%5Em+%2A+x%5En+=+x%5E%28m%2Bn%29+

That is , +2%5E4+%2A+2%5E5+ = +2%5E%284+%2B+5%29+



==> +2%5E9, which is the answer.....


For the second question:


+b%2Ac%5E2%2Ab%5E6%2Ac%5E2 here first of all collect the like terms together(means like variable)



==> +b%2Ab+%5E6+%2A+c%5E2%2Ac%5E2 = +b%5E1%2Ab+%5E6+%2A+c%5E2%2Ac%5E2 you can write b = b%5E1



==> +b%5E%281%2B6%29+%2A+c%5E%282%2B2%29+


==> +b%5E7+%2A+c%5E4+, which is the answer...



Hope you found the explanation useful....

Regards.


Praseena.