SOLUTION: x+y-2z=3 3x-y+z=5 3x+3y-6z=9 plz solve question by crammer rule

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Question 858091: x+y-2z=3
3x-y+z=5
3x+3y-6z=9
plz solve question by crammer rule

Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--

Your Problem:
Solve the following system of linear equations using Cramer's Rule.
x%2By-2z=3
3x-y%2Bz=5
3x%2B3y-6z=9

Solution:
Cramer's Rule is a solution method that uses matrices and their determinants.

Step 1: Write the coefficient matrix and the answer column for your system.



Step 2: Now we find find the determinants of four matrices, D, D%5Bx%5D, D%5By%5D, and D%5Bz%5D.

Matrix D is the coefficient matrix.
%0D%0A+++matrix%283%2C+3%2C+1%2C+1%2C+2%2C+3%2C+-1%2C+1%2C+3%2C+3%2C+-6%29+%0D%0A

The determinant, |D| = 48
 
Matrix Dx is the coefficient matrix with column one replaced with the answer column.
%0D%0A+++matrix%283%2C+3%2C+3%2C+1%2C+2%2C+5%2C+-1%2C+1%2C+9%2C+3%2C+-6%29+%0D%0A
The determinant, |Dx| = 96

Matrix Dy is the coefficient matrix with column two replaced with the answer column.
%0D%0A+++matrix%283%2C+3%2C+1%2C+3%2C+2%2C+3%2C+5%2C+1%2C+3%2C+9%2C+-6%29%0D%0A
The determinant, |Dy| = 48

Matrix Dz is the coefficient matrix with column three replaced with the answer column.
%0D%0A+++matrix%283%2C+3%2C+3%2C+1%2C+2%2C+5%2C+-1%2C+1%2C+9%2C+3%2C+-6%29%0D%0A
The determinant, |Dz| = 0


Step 3. Now that we have these values, we can find x, y, and z.

x = Dx / D = 96/48 = 2
y = Dy / D = 48/48 = 1
z = Dz / D = 0/48 = 0

Check your answer by substituting 2 for x, 1 for y, and 0 for z in the original equations. 

2x + y - z = 3
(2) + (1) - 2(0) = 3
2 + 1 = 3
3 = 3
Check!

3x - y + z = 5
3(2) - (1) + (0) = 5
6 - 1 = 5
5 = 5
Check!

3x + 3y - 6z = 9
3(2) + 3(1) - 6(0) = 9
6 + 3 = 9
9 = 9
Check!

Hope this helps. If you have questions about how to find the determinant of a matrix, here is a nice explanation at PurpleMath:
http://www.purplemath.com/modules/determs2.htm

Mrs. Figgy
math.in.the.vortex@gmail.com