SOLUTION: Solve the system: log x^2=y+3 log x=y-1

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Question 858056: Solve the system:
log x^2=y+3
log x=y-1
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
If your notation means what it is as shown, then the first equation is 2%2Alog%28b%2Cx%29=y%2B3, for the base b, used for both equations. Treat the entire log%28b%2Cx%29 as one of the variables.

The system can be restated:
---------------
y-2log%28b%2Cx%29=-3
-
y-log%28b%2Cx%29=1
---------------

Subtract one equation from the other equation to eliminate y, and solve first for log%28b%2Cx%29; use this to solve for y. You could then continue on to find what x is.