SOLUTION: I paid my bill of $3.75using only coins. I used three times as many dimes as quarters and five more nickels than dimes. How many of each coin did I use?
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Question 857905: I paid my bill of $3.75using only coins. I used three times as many dimes as quarters and five more nickels than dimes. How many of each coin did I use? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I paid my bill of $3.75using only coins. I used three times as many dimes as quarters and five more nickels than dimes.
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d = 3q
n = d + 5
5n + 10d + 25q = 375 cents
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Substitute for "q" and for "n" and solve for "d";;;
5(d+5) + 10d + 25(d/3) = 375
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5d + 25 + 10d + (25/3)d = 375
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15d + (25/3)d = 350
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Multiply thru by 3 to get:
45d + 25d = 1050
70d = 1050
d = 15 (# of dimes)
q = d/3 = 5 (# of quarters)
n = d+5 = 30 (# of nickels)
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Cheers,
Stan H.
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