SOLUTION: Find the equaiton in standard form of the parabola with vertex at (0,0) and focus (0,-3)

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Question 857854: Find the equaiton in standard form of the parabola with vertex at (0,0) and focus (0,-3)
Answer by lwsshak3(11628) About Me  (Show Source):
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Find the equation in standard form of the parabola with vertex at (0,0) and focus (0,-3)
Given parabola opens down:
Its basic equation:
x^2=-4py
axis of symmetry: x=0 or y-axis
p=3 (distance from focus to vertex on the axis of symmetry)
4p=12
Equation of given parabola:
x^2=-12y