Question 857849: Find the vertex, focus, and directrix of the parabola given by the equation (x-1)^2 = 8y-16
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex, focus, and directrix of the parabola given by the equation
(x-1)^2 = 8y-16
(x-1)^2 = 8(y-2)
This is an equation of a parabola that opens up
Its basic equation:
(x-h)^2=4p(y-k), (h,k)=coordinates of the vertex
For given parabola:
vertex:(1,2)
axis of symmetry: x=1
4p=8
p=2
focus(1,4) (p-distance above vertex on the axis of symmetry)
directrix:y=0 (p-distance below vertex on the axis of symmetry)
|
|
|
