SOLUTION: Two cars leave at the same time from towns that are 180 miles apart traveling toward each other. One car travels 10 mph faster than the other. They meet each other after two hours.
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Question 85774: Two cars leave at the same time from towns that are 180 miles apart traveling toward each other. One car travels 10 mph faster than the other. They meet each other after two hours. Find the speed of the faster car. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Two cars leave at the same time from towns that are 180 miles apart traveling toward each other. One car travels 10 mph faster than the other. They meet each other after two hours. Find the speed of the faster car.
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Let x = speed of the faster car
Then
(x-10) = speed of the slower car
:
We know that when they meet the total distance of the two cars will be 180 mi
:
Distance = time * speed:
:
Slow car dist + fast car dist = 180
2(x-10) + 2x = 180
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Simplify, divide by 2
x - 10 + x = 90
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2x = 90 + 10
:
x = 100/2
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x = 50 mph speed of the faster car
:
:
Check solution using distance
2*50 = 100
2*40 = 80
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Total = 180
