SOLUTION: An investor placed a total of $16,000 in two simple interest accounts. One account earned a simple interest rate of 5.9%, and the other earned a simple interest rate of 3.6%. The t

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: An investor placed a total of $16,000 in two simple interest accounts. One account earned a simple interest rate of 5.9%, and the other earned a simple interest rate of 3.6%. The t      Log On

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Question 85761: An investor placed a total of $16,000 in two simple interest accounts. One account earned a simple interest rate of 5.9%, and the other earned a simple interest rate of 3.6%. The two accounts earned a total of $668. How much was invested in each account?
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
.059X+.036(16000-X)=668
.059X+576-.036X=668
.023X=668-576
.023X=92
X=92/.023
X=4000 AMOUNT INVESTED @ 5.9%
16000-4000=12000 INVESTED @ 3.6%.
PROOF
.059*4000+.036*12000=668
236+432=668
668=668