SOLUTION: What is the area of a rectangle with the length of {{{6a^2b}}} and a width of {{{3ab}}}?

Algebra ->  Exponents -> SOLUTION: What is the area of a rectangle with the length of {{{6a^2b}}} and a width of {{{3ab}}}?      Log On


   

Question 857554: What is the area of a rectangle with the length of 6a%5E2b and a width of 3ab?
Answer by ben720(159) About Me  (Show Source):
You can put this solution on YOUR website!


Area = Length times Width
Let A=area
A=%286a%5E2b%29%283ab%29
Reorder factors
A=6%2A3%2Aa%5E2%2Aa%2Ab%2Ab
Extend exponents, multiply 6&3
A=18%2Aa%2Aa%2Aa%2Ab%2Ab
Combine like terms. a*a*a = a^3, b*b = b^2, as there are 3 a's and 2 b's
A=18a%5E3b%5E2

The area of the rectangle is 18a%5E3b%5E2