SOLUTION: An arrow shot into the air is 160x-16x^2 feet above the ground "x" seconds after it is released. During what period of time is the arrow above 384 feet? Please include a step-by-st

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Question 857513: An arrow shot into the air is 160x-16x^2 feet above the ground "x" seconds after it is released. During what period of time is the arrow above 384 feet? Please include a step-by-step explanation of how you got the answer. Thank You.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
160x-16x^2 =384
put in order
-16x^2 +160x-384=0
multiply by -1
16x^2-160x+384=0
divide by 16
x^2-10x+24=0
factor
(x-4)(x-6)=
x=4 and x=6
on its way up and on its way down