SOLUTION: 1) 2x^2-y^2=14 y-2x=-4 use substitution 2) 2x^2-2y^2=56 x^2+y^2=100 Use substitution

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 1) 2x^2-y^2=14 y-2x=-4 use substitution 2) 2x^2-2y^2=56 x^2+y^2=100 Use substitution      Log On


   

Question 857467: 1) 2x^2-y^2=14
y-2x=-4
use substitution
2) 2x^2-2y^2=56
x^2+y^2=100
Use substitution
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1) 2x^2-y^2=14
y-2x=-4 --> y = 2x - 4
sub for y in the 1st eqn
-----------------------
2x^2-2y^2=56 --> x^2 - y^2 = 28 --> x^2 = y^2 + 28
x^2+y^2=100
---
x^2 + y^2 = 100
Sub for x^2
y^2 + 28 + y^2 = 100
2y^2 = 72
y^2 = 36
y = -6, +6
Sub for y to find x in any equation.
You get 4 solutions.