SOLUTION: josie has twice as many nickels as dimes and five less quarters than dimes. if she had a total of $5.95. how much of each coins does she have

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Question 857342: josie has twice as many nickels as dimes and five less quarters than dimes. if she had a total of $5.95. how much of each coins does she have
Answer by ben720(159) About Me  (Show Source):
You can put this solution on YOUR website!



If you Let X=dimes, then
2(X)*0.05 nickels + X*0.1 dimes + (X-5)*0.25 = $5.95
X%2A0.1+%2B+X%2A0.1+%2B+X%2A0.25+-+1.25+=+5.95
Then, add 1.25 to both sides,
X%2A0.1+%2B+X%2A0.1+%2B+X%2A0.25+=+7.20
Combine Like Terms
X%2A0.45+=+7.20
Divide by 0.45 on both sides
X+=+16
You have X dimes, 2X nickels, and X-5 quarters.
Substitute to get 16 dimes, 32 nickels, and 11 quarters.

To check, see if 16%2A0.1+%2B+32%2A0.05+%2B+11%2A0.25+=+5.95
1.6%2B1.6%2B2.75=5.95
5.95=5.95 True

Your final, checked answer is 16 dimes, 32 nickels, and 11 quarters.