SOLUTION: 10 men working for 6 days of 10 hours each finish 5/21 of a piece of work. How many men working at the same rate and for the same number of hours, will be required to complete the

Algebra ->  Rate-of-work-word-problems -> SOLUTION: 10 men working for 6 days of 10 hours each finish 5/21 of a piece of work. How many men working at the same rate and for the same number of hours, will be required to complete the       Log On


   



Question 857298: 10 men working for 6 days of 10 hours each finish 5/21 of a piece of work. How many men working at the same rate and for the same number of hours, will be required to complete the remaining work in 8 days
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
10*6=60 man days
60=5x/21
12=x/21
252=x
16/21*252=4032/21=192 man days needed
192/8=24 men needed to finish the work in 8 more days