SOLUTION: The two straight lines 3y + 2x - 7 = 0 and 2 y = x - 7 intersect at the point P. Q is the point (-9,2) . Find equation of PQ.
Algebra ->
Linear-equations
-> SOLUTION: The two straight lines 3y + 2x - 7 = 0 and 2 y = x - 7 intersect at the point P. Q is the point (-9,2) . Find equation of PQ.
Log On
Question 857292: The two straight lines 3y + 2x - 7 = 0 and 2 y = x - 7 intersect at the point P. Q is the point (-9,2) . Find equation of PQ. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 3y + 2x - 7 = 0 anFind pd 2 y = x - 7 intersect at the point P. Q is the point (-9,2)
Find P solve for x &y
2 x + 3 y = 7 .............1
Total value
1 x -2 y = 7 .............2
Eliminate y
multiply (1)by 2
Multiply (2) by 3
4 x 6 y = 14
3 x -6 y = 21
Add the two equations
7 x = 35
/ 7
x = 5
plug value of x in (1)
2 x + 3 y = 7
10 + 3 y = 7
3 y = 7 -10
3 y = -3
y = -1
P(5,-1) Q(-9,2)
x1 y1 x2 y2
5 -1 -9 2
The general equation of the line when co-ordinates of two points are given is
