Question 857178: find the angle between the given vectors to the nearest tenth of a degree.
u=sq.root5i-8j, v=sq.root5i+j
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the angle between the given vectors to the nearest tenth of a degree.
u=sq.root5i-8j, v=sq.root5i+j
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standard angle with terminal side
thru (sqrt(5),-8) is arctan(-8/sqrt(5)) = 285.62 degrees
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standard angle with terminal side
thru (sqrt(5,1) is arctan(1/sqrt(5) = 65.91 degrees
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Angle between = 285.62-65.91 = 219.71 degrees
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Cheers,
Stan H.
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