SOLUTION: The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean

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Question 857016: The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.5 minutes and a standard deviation of 2.4 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.)
(a) less than 10 minutes
.2083 .
(b) longer than 5 minutes

(c) between 8 and 15 minutes
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

mean of 9.5 minutes and a standard deviation of 2.4 minutes.

a) P(x< 10min)  Yes, z = .2083  P = NORMSDIST(.2083) = .5825

b) P(x> 5min) = 1 - NORMSDIST(-4.5/2.4)

c) P(8 ≤ x ≤ 15) = NORMSDIST(6.5/2.4) - NORMSDIST(-1.5/2.4)



TI function normalcdf(smaller, larger, µ, σ) can also be used