SOLUTION: In how many ways can the digits 8675309 be arranged if the digits must alternate between odd and then even?
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Question 856998: In how many ways can the digits 8675309 be arranged if the digits must alternate between odd and then even? Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! 8675309
860 - Even numbers - 3 total
7539 - Odd numbers - 4 total
Since they must alternate, the numbers must start with an odd number.
