SOLUTION: A spring with a mass 2kg length 0.5m. A force of 25.6 N is required to maintain its stretched to length of 0.7m. If tie spring stretched to a length of 0.7m and then released with

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Question 856987: A spring with a mass 2kg length 0.5m. A force of 25.6 N is required to maintain its stretched to length of 0.7m. If tie spring stretched to a length of 0.7m and then released with initial velocity 0. Find composition of the mass at any time(t) can be written as acosxt +bsinxt.find the value of a,b,x.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
m=2
L=0.5
.
.
F=kx
25.6=k%280.7%29
k=36.57
.
.
y=a%2Acos%28xt%29%2Bb%2Asin%28xt%29
When t=0, y=0.7,
0.7=a%2A1%2Bb%2A0
a=0.7
When t=0, dy%2Fdt=0
dy%2Fdt=-xa%2Asin%28xt%29%2Bxbcos%28xt%29=0
-xa%2A0%2Bxb%2A1=0
b=0
y=0.7cos%28xt%29
x=sqrt%28k%2Fm%29
x=sqrt%2836.57%2F2%29
x=sqrt%2818.286%29
x=4.28
So then,
highlight%28y=0.7cos%284.28t%29%29