SOLUTION: How do you solve (x-2)(x+3)-(x+5)(x-7)=1

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Question 856972: How do you solve (x-2)(x+3)-(x+5)(x-7)=1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Expand, combine Like Terms and solve

(x-2)(x+3)-(x+5)(x-7)=1

 x^2 + x - 6 - (x^2 - 2x - 35) = 1

 x^2 + x - 6 - x^2 + 2x + 35) = 1

       3x + 29 = 1

          3x =  -28

           x = -28/3