SOLUTION: The product of two consecutive odd integers is 57 less than 9 times their sum. Find the two integers.

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Question 856719: The product of two consecutive odd integers is 57 less than 9 times their sum. Find the two integers.
Found 2 solutions by CubeyThePenguin, josgarithmetic:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: x, (x+1)

x(x+1) = 9(x + (x+1)) - 57
x^2 + x = 9(2x+1) - 57
x^2 + x = 18x - 48
x^2 - 17x + 48 = 0


The solutions to this equation are not integers.

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
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product of two consecutive odd integers is,...
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n%28n%2B2%29=-57%2B9%28n%2Bn%2B2%29

n%5E2%2B2n=9%282n%2B2%29-57
n%5E2%2B2n=18n%2B18-57
n%5E2-16n%2B57-18=0
n%5E2-16n%2B39=0
%28n-3%29%28n-13%29=0
system%28n=3%2Cor%2Cn=13%29

Check each of these separately and see if one or both of them will work.