SOLUTION: A poll of 500 college students showed that 38% of them perform some volunteer work. Construct a 99% confidence interval for the proportion of all students who perform some volunt

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Question 856374: A poll of 500 college students showed that 38% of them perform some volunteer work. Construct a 99% confidence interval for the proportion of all students who perform some volunteer work.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A poll of 500 college students showed that 38% of them perform some volunteer work. Construct a 99% confidence interval for the proportion of all students who perform some volunteer work.
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sample proportion:: 0.38
ME = 2.5758*sqrt[0.38*0.62/500] = 0.0559
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99%CI: 0.38-0.0559 < p < 0.38+0.0559
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Cheers,
Stan H.
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