SOLUTION: Four cards are drawn from a pack of 52 cards. What is the probability that a card from each of the four suits is obtained?
I have the following:
13/52 (probability of 1st card
Algebra ->
Probability-and-statistics
-> SOLUTION: Four cards are drawn from a pack of 52 cards. What is the probability that a card from each of the four suits is obtained?
I have the following:
13/52 (probability of 1st card
Log On
Question 856341: Four cards are drawn from a pack of 52 cards. What is the probability that a card from each of the four suits is obtained?
I have the following:
13/52 (probability of 1st card of 1 suit) x 12/51 (probability of 2nd card from same suit) x 11/50 (prob. 3rd card from same suit) x 10/49 (prob. of 4th card from same suit) = 11/4165 [No. of desired outcomes]
I divided this by 52C4 [No. of possible outcomes] to get answer: 9.755 x 10 to power of -9
Can you advise on my method please?
Thanking you. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! The probability of the first card is 1 (any one will do).
Card 2 probability is 3*13/51 = 13/17.
Card 3 probability is 2*13/50 = 13/25.
Card 4 probability is 13/49 = 13/49
.
13^3/(17*25*49)
=2197/20825
=~ 0.1055
.
Ed
