SOLUTION: My daughter is still having trouble with area and trinomial/polynomial problems...one of them tonight is similar to the last one but still confused on the process...they have not s

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: My daughter is still having trouble with area and trinomial/polynomial problems...one of them tonight is similar to the last one but still confused on the process...they have not s      Log On


   



Question 856332: My daughter is still having trouble with area and trinomial/polynomial problems...one of them tonight is similar to the last one but still confused on the process...they have not started dividing polynomials yet so....the area of a rectangular granite countertop is 12x^2 + 10x - 12 and the width is 12x + 3 what is the length? can you help with a step by step method on these type of questions? She had a test last Friday and needs a little help...
thanks in advance for your support

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Do you mean the width is 12x+3 or 2x+3??
12x^2 + 10x - 12
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


12%2Ax%5E2%2B10%2Ax-12 Start with the given expression.



2%286x%5E2%2B5x-6%29 Factor out the GCF 2.



Now let's try to factor the inner expression 6x%5E2%2B5x-6



---------------------------------------------------------------



Looking at the expression 6x%5E2%2B5x-6, we can see that the first coefficient is 6, the second coefficient is 5, and the last term is -6.



Now multiply the first coefficient 6 by the last term -6 to get %286%29%28-6%29=-36.



Now the question is: what two whole numbers multiply to -36 (the previous product) and add to the second coefficient 5?



To find these two numbers, we need to list all of the factors of -36 (the previous product).



Factors of -36:

1,2,3,4,6,9,12,18,36

-1,-2,-3,-4,-6,-9,-12,-18,-36



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -36.

1*(-36) = -36
2*(-18) = -36
3*(-12) = -36
4*(-9) = -36
6*(-6) = -36
(-1)*(36) = -36
(-2)*(18) = -36
(-3)*(12) = -36
(-4)*(9) = -36
(-6)*(6) = -36


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 5:



First NumberSecond NumberSum
1-361+(-36)=-35
2-182+(-18)=-16
3-123+(-12)=-9
4-94+(-9)=-5
6-66+(-6)=0
-136-1+36=35
-218-2+18=16
-312-3+12=9
-49-4+9=5
-66-6+6=0




From the table, we can see that the two numbers -4 and 9 add to 5 (the middle coefficient).



So the two numbers -4 and 9 both multiply to -36 and add to 5



Now replace the middle term 5x with -4x%2B9x. Remember, -4 and 9 add to 5. So this shows us that -4x%2B9x=5x.



6x%5E2%2Bhighlight%28-4x%2B9x%29-6 Replace the second term 5x with -4x%2B9x.



%286x%5E2-4x%29%2B%289x-6%29 Group the terms into two pairs.



2x%283x-2%29%2B%289x-6%29 Factor out the GCF 2x from the first group.



2x%283x-2%29%2B3%283x-2%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%282x%2B3%29%283x-2%29 Combine like terms. Or factor out the common term 3x-2



--------------------------------------------------



So 2%286x%5E2%2B5x-6%29 then factors further to 2%282x%2B3%29%283x-2%29



===============================================================



Answer:



So 12%2Ax%5E2%2B10%2Ax-12 completely factors to 2%282x%2B3%29%283x-2%29.



In other words, 12%2Ax%5E2%2B10%2Ax-12=2%282x%2B3%29%283x-2%29.



Note: you can check the answer by expanding 2%282x%2B3%29%283x-2%29 to get 12%2Ax%5E2%2B10%2Ax-12 or by graphing the original expression and the answer (the two graphs should be identical).


2*(6x^2+5x-6)
6x^2+2x+3x-6
2 (3x-2) (2x+3)
(6x-4)*(2x+3)
the length is (6x-4)