SOLUTION: 2x-3y-10=0 and x^2+xy+y^2+2x+y-6=0. Solve please

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Question 856324: 2x-3y-10=0 and x^2+xy+y^2+2x+y-6=0. Solve please
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the linear equation for x in terms of y (or the other way around if you want); substitute this into the conic section equation, and simplify. You are looking to solve a quadratic equation in ONE variable which may have two solutions, or possibly one solution. Can you do this without more help?

"No."

2x-3y-10=0
2x=3y%2B10
highlight_green%28x=%283%2F2%29y%2B5%29---Use this in the quadratic equation and again later after finding values for y.
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The substitution:
%283y%2F2%2B5%29%5E2%2B%283y%2F2%2B5%29y%2By%5E2%2B2%283y%2F2%2B5%29%2By-6=0
%289%2F4%29y%5E2%2B15y%2B25%2B%283%2F2%29y%5E2%2B5y%2By%5E2%2B3y%2B10%2By-6=0
...combine like terms and simplify ...
%2829%2F4%29y%5E2%2B%2833%2F2%29y%2B29=0
highlight_green%2829y%5E2%2B66y%2B116=0%29 ---- you could try to factor this, but much easier to use the general solution to a quadratic equation.
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Discriminant is 66%5E2-4%2A29%2A116=4356-113456=-109100
The solution will contain an Imaginary component. The discriminant is less than zero.
! you would expect the two graphs to share not any points; no intersections.
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Another try done on paper but solving first for x instead of y in the linear equation and then substituting, gave me after simplifications, highlight_green%2819x%5E2-46x%2B732=0%29;
and the discriminant, "b^2-4*a*c", is highlight_green%28-53516%29, a value less than zero. This again means that the solution for x will contain an Imaginary component. The given conic section and the given line DO NOT INTERSECT!