SOLUTION: The sum of two times one number and three times another is 29. The difference between twice the first number and second is 1. Solve algebraically to find the numbers.

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Question 856308: The sum of two times one number and three times another is 29. The difference between twice the first number and second is 1. Solve algebraically to find the numbers.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of two times one number and three times another is 29. The difference between twice the first number and second is 1. Solve algebraically to find the numbers.
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Equations:
2x + 3y = 29
2x - y = 1
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Subtract and solve for "y":
4y = 28
y = 7
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Solve for "x":
2x - y = 1
2x - 7 = 1
2x = 8
x = 4
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Cheers,
Stan H.
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