SOLUTION: Find the equation of a line perpendicular to y = −(1/2)x + 132 and passing through the point (3, 14)

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Question 856246: Find the equation of a line perpendicular to y = −(1/2)x + 132 and passing through the point (3, 14)







Found 2 solutions by Fombitz, lwsshak3:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
m%2A%28-1%2F2%29=-1
m=2
.
.
y=2x%2Bb
Use the point to solve for b
14=2%283%29%2Bb
b=14-6
b=8
.
.
highlight%28y=2x%2B8%29

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of a line perpendicular to y = −(1/2)x + 132 and passing through the point (3, 14)
***
Form of equation for a line: y=mx+b, m=slope, b=y-intercept
Slope of given line=-1/2
Slope of line perpendicular to given line=negative reciprocal of slope of given line=-(1/(-1/2)=2
Equation of perpendicular line:
y=2x+b
solve for b using coordinates of given points line passes thru.
14=2*3+b
b=8
Equation: y=2x+8