SOLUTION: The probability distribution of x, the number of defective tires on a random automobile at an inspection station, is given in the following table: x = 0, 1, 2, 3, 4 P(x) = .5

Algebra ->  Probability-and-statistics -> SOLUTION: The probability distribution of x, the number of defective tires on a random automobile at an inspection station, is given in the following table: x = 0, 1, 2, 3, 4 P(x) = .5      Log On


   

Question 856127: The probability distribution of x, the number of defective tires on a random automobile at an inspection station, is given in the following table:
x = 0, 1, 2, 3, 4
P(x) = .54, .16, .06, .04, .20
What is the standard deviation of x?
What is mean value of x?
Calculate P(1 < x What is probability there were no more than 3 defective tires?
What is P(x>3)?
What is P(x Thanks for your time!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Expected value and SD				

n	p	np	n*n*p	

0	0.54	0	0	

1	0.16	0.16	0.16	

2	0.06	0.12	0.24	

3	0.04	0.12	0.36	

4	0.2	0.8	3.2	

		1.2	3.96	

variance = 3.96 - (1.2)^2 = 2.52

SD = sqrt%282.52%29 = 1.5875

mean = 1.2

P(x ≥ 3)

Using TI: The syntax is normalcdf(smaller, larger, µ, σ)

Note: 100 is used as the larger value to be at least 5 standard deviations from the mean.

P(x ≥ 3) = 1 - normalcdf(3,100,1.2, 1.5875)