Hi,
P(z < 1.05) = NORMSDIST(1.05)= .8531
(85.31% of the area under the normal curve is to the left of z = 1.05)
P(0< z ≤ .24) = NORMSDIST(.24) - .5 = .5948 - .5 = .0948
Normal distribution:
Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Note: z = 0 (represents the mean) 50% of the area under the curve is to the left and %50 to the right
