Question 855887: I made a mistake and put it in wrong got an different one now. ok thanks we only get three chances. ok thanks
#1
A card is drawn randomly from a standard 52-card deck. Find the following:
Write all answers as simplified fractions.
Probability the card drawn is a face card 3/13 is right.
Probability the card drawn is not a face card. 10/13 is right.
Odds in favor of drawing a face card
Odds against drawing a face card
#2
A card is drawn randomly from a standard 52-card deck. Find the following:
Write all answers as simplified fractions.
Probability the card drawn is a face card. 3/13 is right.
Probability the card drawn is not a face card. 10/3 is right.
Odds in favor of drawing a face card
Odds against drawing a face card
#7
A bag contains 1 gold marbles, 9 silver marbles, and 23 black marbles. Someone offers to play this game: You randomly select one marble from the bag. If it is gold, you win $4. If it is silver, you win $3. If it is black, you lose $1.
What is your expected value if you play this game?
#8
A bag contains 3 gold marbles, 8 silver marbles, and 23 black marbles. Someone offers to play this game: You randomly select one marble from the bag. If it is gold, you win $4. If it is silver, you win $3. If it is black, you lose $1.
What is your expected value if you play this game?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! Hi,
Re TY
Super!!! You have a great week as well.
Write all answers as simplified fractions.
1 and 2 identical
12 face cards (K, Q, J in each of the 4 suits)
card drawn
P(facecard) = 12/52 = 3/13
P(not a facecard) = 40/52 = 10/13
Write all answers as simplified fractions.
odds in favor : 3:10, odds against: 10:3
7) 33 marbles: 1 gold, 9 silver and 23 black marbles.
E = $4(1/33) + $3(9/33) - $1(23/33) = $4/33 + $27/33 - $23/33 = $8/33 = $0.24
7) 34 marbles: 3 gold, 8 silver and 23 black marbles.
E =$4(3/34) + $3(8/34) - $1(23/34) = $13/34 = $0.38
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