SOLUTION: if 2tanx = secx then 4cot^2x-8tan^2x =? i tried this question with all identities that i have read such as sec^2x-tan^2x=1 and others icant get the annswer ... can you please the p

Algebra ->  Trigonometry-basics -> SOLUTION: if 2tanx = secx then 4cot^2x-8tan^2x =? i tried this question with all identities that i have read such as sec^2x-tan^2x=1 and others icant get the annswer ... can you please the p      Log On


   



Question 855708: if 2tanx = secx then 4cot^2x-8tan^2x =? i tried this question with all identities that i have read such as sec^2x-tan^2x=1 and others icant get the annswer ... can you please the problem in step by step the answer they have given is 28/3..
please let me know.

Found 2 solutions by ramkikk66, josgarithmetic:
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Given that 2 tan x = sec x
i.e. 2 * sin x / cos x = 1 / cos x
Assuming cos x is not 0, (in which case tan x would be infinity) we can cancel
out the 2 cos x's in the denominators to get the equation
2 * sin x = 1
or sin x = 1/2
Now the other ratios can be computed.
cos x = sqrt(1 - sin^2 x) = sqrt (1 - 1/4) = sqrt%283%29%2F2 (+ or -)
tan x = sin x / cos x = 1+%2F++sqrt%283%29 (+ or -)
cot x = 1 / tan x = sqrt%283%29 (+ or -)

Now, the given exp is 4*cot^2 x - 8 * tan^2 x
= 4+%2A+3+-+8+%2A+1%2F3+=+12+-+8%2F3+=+28%2F3

Hope this helps :)


Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The first equation is like these steps:

2sin%28x%29%2F%28cos%28x%29%29=1%2F%28cos%28x%29%29
%282sin%28x%29cos%28x%29%29%2F%28cos%28x%29%29=cos%28x%29%2F%28cos%28x%29%29
2sin%28x%29=1
-
x=pi%2F6 or x=%285%2Api%29%2F6; how does that work for the value of your second equation?