SOLUTION: chris has $6.20 in quarters, dimes and nickels. he has three more quarters than dimes. The number of nickels is one more than twice the number of dimes. find the number of each coi

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Question 85568: chris has $6.20 in quarters, dimes and nickels. he has three more quarters than dimes. The number of nickels is one more than twice the number of dimes. find the number of each coin ????
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Answer by stanbon(75887) About Me  (Show Source):
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Chris has $6.20 in quarters, dimes and nickels. he has three more quarters than dimes. The number of nickels is one more than twice the number of dimes. find the number of each coin ????
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Let number of dimes be "x"; Value of these is 10x cents
Number of quarters is "x+3"; Value of these is 25(x+3) = 25x+75 cents
Number of nickels is "2x+1"; Value of these is 5(2x+1) = 10x+5 cents
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EQUATIOn:
value + value + value = 620 cents
10x + 25x+75 + 10x+5 = 620
45x = 540
x = 12 (number of dimes)
x+3 = 15 (number of quarters)
2x+1 = 25 (number of nickels)
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Cheers,
Stan H.