SOLUTION: The base of a right triangle is decreasing at a rate of 2 inches per minute, and the height of the triangle is increasing at a rate of 4 inches per minute. When the base of the tri

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Question 855600: The base of a right triangle is decreasing at a rate of 2 inches per minute, and the height of the triangle is increasing at a rate of 4 inches per minute. When the base of the triangle is 2 feet and the height is 3 feet, how fast is the area of the triangle changing in square inches per minute?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The way I see it, this is a calculus problem.
With t= time (in minutes) counted from the moment the base of the triangle is 2 feet and the height is 3 feet,
the base (in inches), height (in inches), and area (in square inches) are all functions of t :
base=2%2A12-2t=24-2t
height=3%2A12%2B4t=36%2B4t

The rate of change of the area (in square inches per minute) is
dArea%2Fdt=12-8t which changes with time.
At t=0 (the moment the base of the triangle is 2 feet and the height is 3 feet)
dArea%2Fdt=12-8%2A1=highlight%2812%29

Without invoking calculus, the only solution I see is saying that the rate is the slope of the tangent to the graph.
With x=t and y=Area-432=12t-4t%5E2=12x-4x%5E2 the graph would be
graph%28300%2C300%2C-5%2C5%2C-25%2C25%2C12x-4x%5E2%2C12x%29 .
The tangent y=kx , with slope k passes through the origin
and intersects y=12x-4x%5E2 at only one point.
That means that kx=12x-4x%5E2 must have only one solution.
kx=12x-4x%5E2<-->4x%5E2-12x%2Bkx=0<-->4x%5E2%2B%28k-12%29x=0<-->x%284x%2Bk-12%29=0
has the solutions x=0 and x=%2812-k%29%2F4 .
Those solutions are the same only when 12-k=0<-->k=12 ,
which makes the line tangent.
A line with another slope would intersect the graph at two different points, with x=0 , and x=%2812-k%29%2F4 .