P(B)=0.2 P(A|B)=0.7 P(B')=0.8 AND P(A|B')=0.9 FIND P(B|A) Let P(A&B')=w, P(A&B)=x, P(A'&B)=y, P(A'&B')=z, then (1) w+x+y+z=1 (2) P(B)= x+y = 0.2 (3) P(A|B) = x/(x+y) = 0.7 (4) P(B') = w+z = 0.8 (5) P(A|B') = (w+x)/(w+z) = 0.9 From (1) and (2), (6) w+z = 0.8 From (2) and (3), get (7) x=0.14 (8) y=.06 From (4) and (5) (9) w+x = 0.72 from (7) and (9) (10) w = 0.58 From (6) and (10) (11) z = 0.22 P(B|A) = x/(x+w) = 0.14/(0.14+0.58) = 0.14/0.72 = 14/72 = 7/36 Edwin