SOLUTION: What is the variation shown by these two equations: z=(k√x)/y^2 z=kx^2 √y I need help understanding how to explain what variation is being used. Thanks

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: What is the variation shown by these two equations: z=(k√x)/y^2 z=kx^2 √y I need help understanding how to explain what variation is being used. Thanks      Log On


   

Question 855315: What is the variation shown by these two equations:
z=(k√x)/y^2
z=kx^2 √y
I need help understanding how to explain what variation is being used. Thanks
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
First one: z varies jointly as x to the half power and inversely as y squared.
Second one: I will not do this one for you, but it is too a variation of how z varies with x and y and shows the same proportionality constant, k. If an "independent" variable is in a numerator position, it is "jointly"; and if an independent variable is in a denominator position, it is "inversely".