SOLUTION: We throw a fair dice 4 times. The throws are independent among them. i) What is the probability that we got at least one "6"? ii) What is the probability that we got at least o

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Question 855270: We throw a fair dice 4 times. The throws are independent among them.
i) What is the probability that we got at least one "6"?
ii) What is the probability that we got at least one "6" granted that we didn't get any "1"?
iii) What is the probability that we didn't get any "1" granted that we got at least one "6"?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
i) P(at least one six) = 1 - P(no six) = 1 - (5/6)^4 = = 1-binomcdf(4,1/6,0)= .5178
ii) P(at least one six | no one) = 1 -(4/5)^4= 1-binomcdf(4,1/5,0)= .5904
iii) P(No 1 | at least one six) = .5904