SOLUTION: Suppose that the function g is defined, for all real numbers, as follows. g(x)= 1 if x < -2 g(x)= -(x-1)^2 + 1 if -2 < or = to x < 1 g(x)= 1 ___ x +

Algebra ->  Functions -> SOLUTION: Suppose that the function g is defined, for all real numbers, as follows. g(x)= 1 if x < -2 g(x)= -(x-1)^2 + 1 if -2 < or = to x < 1 g(x)= 1 ___ x +       Log On


   

Question 855267: Suppose that the function g is defined, for all real numbers, as follows.

g(x)= 1 if x < -2

g(x)= -(x-1)^2 + 1 if -2 < or = to x < 1

g(x)= 1
___ x + 1 if x is > or equal to 1
2

Find the following.
g (-5)=
g (0) =
g (1) =
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
g%28-5%29=1 since x%3C-2
g%280%29=-%280-1%29%5E2%2B1=-1%2B1=0 since -2%3Cx%3C1
g%281%29=%281%2F2%29%281%2B1%29=%281%2F2%29%282%29=1 since x=1