SOLUTION: Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.       Log On


   

Question 855247: Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.
x^2+(y-3)^2 = 16
This is an equation of a circle with center at (0,3) and radius=4
domain: {x|[-4,4]}
range: {y|[-1,7]}
see graph below:
y=(16-x^2)^.5+3